Question 116265
x^2+y^2=25 
x-2y=-5 
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x = 2y-5
Substitute to get:
(2y-5)^2 + y^2 = 25
4y^2-20y+25 + y^2 = 25
5y^2-20y=0
5y(y-4) = 0
y = 0 or y = 4
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Substitute y = 0 into x-2y=-5 to get x=-5
Substitute y = 4 into x-2y=-5 to get x-8 = -5; x = 3
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Solution: (-5,0) and (3,4)
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Cheers,
Stan H.