Question 115231
Since f(x) is really "y", this means {{{h(x)=y-3}}}. So what this transformation does is shift every point down 3 units. 


So let P be the point (2,3) 


{{{drawing(500,500,-6,6,-6,6,
grid(1),
circle(2,3,0.08),
circle(2,3,0.10)
)}}} Here's the point (2,3)


Now shift the point 3 units down 


{{{drawing(500,500,-6,6,-6,6,
grid(1),
circle(2,3,0.08),
circle(2,3,0.10),
green(arc(2,0.5,1,1,270,90)),
green(arc(2,1.5,1,1,270,90)),
green(arc(2,2.5,1,1,270,90)),
circle(2,0,0.08),
circle(2,0,0.10)
)}}}



So our new point is (2,0)



So for any P in general, the coordinates are (x,y-3) where x and y could be any number.