Question 115103
Since the degree of the numerator is 1 and the degree of the denominator is 2, the degree of the numerator is less than the degree of the denominator. So this always means the horizontal asymptote is {{{y=0}}}


Here's the graph



{{{ graph(500,500,-10,10,-10,10,0, (3x-25)/(x^2-9))}}}