Question 16902
You have probably forgotten that...anything to the zero power is equal to 1.

If {{{x^n = 1}}} then n must be 0 because: {{{x^0 = 1}}}, so...
If {{{3.5^n = 1}}}, then n must be 0 because {{{3.5^0 = 1}}}

Or you can resort to logarithms to show the same thing:

{{{3.5^n = 1}}} Take the log of both sides.
{{{nlog(3.5) = log(1)}}} Divide both sides by log(3.5)
{{{n = log(1)/log(3.5)}}} But log(1) = 0, so...
{{{n = 0/0.544}}}
{{{n = 0}}}