<PRE><B>Question 109156</B>
15/x - 15/x+2 = 2
;
{{{15/x}}} - {{{15/((x+2))}}} = 2
:
The common denominator will be x(x+2)
Multiply equation by that:
x(x+2)*{{{15/x}}} - x(x+2)*{{{15/((x+2))}}} = x(x+2) * 2
:
Cancel out the denominators and you have:
15(x+2) - 15x = 2x(x+2)
:
15x + 30 - 15x = 2x^2 + 4x
:
The 15x&#39;s cancel; subtract 30 from both sides, you have a quadratic equation
 2x^2 + 4x - 30 = 0
:
Factor this to:
(2x - 6)(x + 5) = 0
:
Two solutions:
2x = +6
x = 6/2
x = 3
and
x = - 5
:
Check both solutions in the original equation:
x = 3
{{{15/3}}} - {{{15/((3+2))}}} = 2
  5 - 3 = 2; a good solution
:
{{{15/(-5)}}} - {{{15/((-5+2))}}} = 2
  -3  - (-5) = 2; also a good solution
:
Did this help you understand this? Any questions?  </PRE>