Question 1956
cheers for the original...the thing i have issue with is the value 200degree for the angle ACD and CAB. We usually quote internal angles, but the triangle ACP already has 400 degrees worth of angles.

I basically have a triangle ACP and a circle drawn such that A and C are on the circumference and P is outside. Between A and P the line cuts the circle again at B and again, between C and P the line cuts the circle again at D.

AB is equal in length to CD.

Only stumbling block is the value 200.

Jon