Question 104934
Well...
The general form of the equation that gives the height (h) of an object propelled upwards, as a function of time (t) is:
{{{h(t) = -(1/2)gt^2+v[0]t+h[0]}}} where: h is the height in feet, t is the time in seconds, g is the acceleration due to gravity ({{{g = 32 ft/sec^2)}}}, {{{v[0]}}} is the initial velocity of the object, and {{{h[0]}}} is the initial height of the object.
If you wanted to graph such an equation (it would be a parabola opening downward), it would be written as:
{{{y = -16t^2+v[0]t+h[0]}}}
The x in your equation is a replacement variable for the time, t.
The first term {{{-16t^2}}} is negative because of the downward effect of gravity on the object.
Just for fun, let's see what your equation would look like when graphed:
{{{graph(600,400,-5,8,-5,200,-16x^2+90x+50)}}}