Question 103350
{{{((15x^2+10x )/ (2x^2-13x +20))*((2x^2-3x-5) / (30x^3 + 20x^2))}}}
Factor each separately first;
{{{(5x(3x+2)/(2x-5)(x-4))*((2x-5)(x+1)/(10x^2)(3x+2))}}}
I've highlighted all those we can cancel out;
{{{(highlight(5x)*highlight(3x+2))/(highlight(2x-5)*(x-4))*(highlight(2x-5)*(x+1))/(highlight(10x^2)*highlight(3x+2))}}}
Now let's cancel out;
{{{(cross(5x)*cross(3x+2))/(cross(2x-5)*(x-4))*(cross(2x-5)*(x+1))/(cross(10x^2)*cross(3x+2))}}}
So you are left with;
{{{(x+1)/(2x(x-4))}}}
Hope you got it
:)