Question 102139
You can write this:
:
{{{(4x^2-9)/(4x^2+12x+9)}}} * {{{1/(6x-9)}}}
:
Recognize that one is a difference of squares, the other is a perfect square:
When factored you have;
{{{((2x+3)(2x-3))/((2x+3)(2x+3))}}} * {{{1/(3(2x-3))}}}
:
Note you can cancel out (2x+3) and (2x-3) leaving you with:
{{{1/(2x+3)}}} * {{{1/3}}} = {{{1/(3(2x+3))}}}