Question 101232
h(x)=6/x^2 + 8
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I'll assume your problem is as follows:
h(x) = [6/x^2] + 8 
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You want f{g(x)]=h(x)
Let g(x)= 1/x^2
Then Let f(x)=6x + 8
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Then f[g(x)]
= f[1/x^2]
=6(1/x^2)+8 
= [6/x^2]+8
=h(x)
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Cheers,
Stan H.