Question 98908
let perimeter of a square=x
then each side is x/4 and the area A=(x/4)^2=x^2/16
let circle circumference=y
so {{{2pi*r=y}}}
{{{r=y/2pi}}}
{{{A=pi*r^2=pi*(y/2pi)^2}}}
the area of a circle is the green line in the graph. The area of a circle is larger than the area of a square for all measurements perimeter and circumference. They approach each other as they approach zero.
Ed
{{{graph(500,500,-10,10,-10,10,(x/4)^2,3.14159*(x/(2*3.14159))^2)}}}