Question 98545
log4(x-2)+ log4(x+6)=2
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Note: Keep the "base 4" in mind
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log(x-2)(x+6) = 2
(x-2)(x+6) = 4^2
x^2+4x-12 = 16
x^2+4x-28=0
x = [-4 +- sqrt(16-4*-28]/2

x = [-4 +- sqrt(128)]/2
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x = [-4 + 8sqrt(2)]/2 = -2+4sqrt2
OR
x = [-4 - 8sqrt(2)]/2 = -2-4sqrt2

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Cheers,
Stan H.