Question 95169
 find two different rectangles with the same perimeter and the same area. Tried all kinds of different combos of numbers. I know sides of 0 will work, but that isn't a rectangle.
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Let x = length and y = width
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Perimeter = area
2x + 2y = x*y
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2y - xy = -2x
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y(2-x) = -2x
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y = {{{(-2x)/((2-x))}}}; plot this equation
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Here is a graph which plots the length as x and the width as y, which has
perimeter = area (for x > 2).
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I should have added here the statement, 
"Any value greater than 2, that you plug in for x in the above equation, will yield a value for y which will satisfy the problem."
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{{{ graph( 300, 200, -2, 10, -3, 10, (-2x)/(2-x)) }}}
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A couple integer values 6 by 3, 4 by 4, non-integers are unlimited, 
10 by 2.5, 12 by 2.4, 22 by 2.2, etc.
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