Question 93251
Simplify completely: (e4f/g) divided by (ef3/g3)

    ==>  (e^4f/g)/(ef^3/g^3)
    
    ==> (e^4fg^-1/ef^3g^-3)     [a^-m = 1/a^m]

   ==>   e^4-1f^1-3g^-1+3       [ a^m/a^n = a^m-n)

   ==>   e^3f^-2g^2
                   
  ==>  e^3g^2/f^2               [a^-m = 1/a^m]