Question 92998
(16-x^2) / (x^3-2x^2-8x)
:
Convert (16-x^2) to -1(x^2 - 16), then we have
{{{(-1(x^2-16))/((x^3-2x^2-8x))}}} = {{{(-1(x-4)(x+4))/(x(x^2-2x-8))}}} = {{{(-1(x-4)(x+4))/(x(x-4)(x+2))}}} = {{{(-1(x+4))/(x(x+2))}}} = {{{-((x+4))/(x(x+2))}}}
:
Could you follow this OK?