Question 13214
Do you mean y= -1/3 x + 23/3???  If so, then you need to start with the y-intercept at the point 23/3, which is almost up to 8 units.  


From this point measure off a slope of -1/3.  This is to say, it is a RISE of -1 and a run of 3.  So from the point that you just graphed on the y axis, and measure DOWN 1 unit, then move 3 unit to the right, and put a point.   Connect the two points and it should look like this:
{{{ graph ( 300,300, -10, 10, -10, 10, (-1/3)(x) + 23/3) }}}


R^2 at SCC