Question 89336
2(x-5)^2=3               First u got to do is make one side equals to zero

So in this, its easy to take the 3 to other side. So subtact 3 from both sides.

2(x-5)^2-3 = 3-3
2(x-5)^2-3 = 0

Now solve the expand the brackets.

2[x^2-10x+25]-3 = 0
2x^2-20x+50-3 = 0
2x^2-20x+47 = 0

use the quadratic formulae to solve for x


{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 

x = 6.22            or          x=3.78