Question 89024
Question:


7-(-y-5)= 2(y+3)-6(y+1)
 
want to know if I should distributive only the neg. sign to the -y or the 7
at the beginning of the problem, I came up with 5 over 11y
but text book states -12 over 5


Answer:

7-(-y-5)= 2(y+3)-6(y+1)


For solving this you have to remove the parenthesis first.

Here negative sign is distributive only to -y and -5


Hope you are familiar with multiplication of signs...


here -(-y) = +y

 -(-5) = +5

2(y) = 2y

2(3) = 6

-6(y) = -6y

-6(1) = -6


so 7-(-y-5)= 2(y+3)-6(y+1) 

==> 7 + y + 5 = 2y + 6 - 6y - 6


==> 7 + 5 + y = 2y - 6y + 6 - 6


==> 12 + y = -4y 


Add 4y on both sides.....


==> 12 + y + 4y = -4y + 4y



==> 12 + 5y = 0


Subtract 12 from both sides....



==> 12 + 5y - 12 = 0 - 12



==> 5y  = -12


Divide both sides by 5


==> 5y/5 = -12/5



==>{{{ y = -12/5}}} 



Hope you found the explanation useful.


Regards.


Praseena.