Question 89024

   7-(-y-5)= 2(y+3)-6(y+1)

want to know if I should distributive only the neg. sign to the -y or the 7
at the beginning of the problem, I came up with 5 over 11y
but text book states -12 over 5

  The - sign should be distributive only to -y &-5   and not 7
  
  The solution goes like this : 7-(-y-5) = 2(y+3)-6(y+1)
                                  7+y+5  = 2y+6-6y-6
                                     y+12 = -4y+0
                                    y+4y  = -12
                                       5y = -12   or y = -12/5