Question 88155
it doesn't look like much like this: {{{ x - 7sqrt(x) + 6 = 0 }}}. However, let {{{ y=sqrt(x) }}}, which means that {{{ y^2 = x }}}. We now can re-write this as: {{{ y^2 - 7y + 6 = 0 }}} which is a quadratic you can solve by factorisation. Once you have your answers for y, put them into {{{ y^2 = x }}} to find your values for x.


cheers
Jon