Question 88114

    the length of a rectangle is 2 in. more than twice its width. if the perimeter of the rectangle is 34 in, find the dimension of the rectangle

      Let the width of the rectangle  be= b = 2x
      Then the length of the rectangle  = l = 2x+2
      The perimeter of the rectangle = p = 34 in
                                   p = 2(l+b)
                                  34 = 2(2x+2+2x)
                                 34/2= 4x+2
                                17-2 = 4x
                                  4x = 15
                                   x = 15/4 = 3.75  
   The dimensions of the rectangle are b = 2(3.75) = 7.5 inch
                                       l = 2(3.75)+2 = 9.5 inch