Question 88146

  each of the equal sides in an isosceles triangle exceeds the base by 5 in. if the perimeter is 100in., what are the lengths of the three sides ?

     Let the base of an isosceles triangle = x  in
       then the equal sides of the triangle = x+5  in
         the perimeter of the triangle  is  = 100 in
                 perimeter of the triangle  =  sum of all the three sides of the triangle

                                 p = x+(x+5)+(x+5)
                               100 = 3x+10
                            100-10 = 3x
                                3x = 90
                                 x = 90/3 = 30
     The sides of the triangle are x = 30 inch
                                 x+5 = 30+5 = 35 inch
                                 x+5 = 30+5 = 35 inch