Question 85837
{{{(x^2+4x-45)}}}=0 [factor]
(x+9)(x-5)=0 [set each factor equal to zero and solve for the x-term]
.
x+9=0
x=-9
.
and
.
x-5=0
x=5
.
check by plugging the values of x back into the original equation and solve.