```Question 84707
26)given line is 3x + y = -3

==> y = - 3x - 3

This is of the form y = mx + c where m is the slope.

So slope of the given line = -3

So slope of the required line is also -3 as parallel lines have the same slope.

It passes through (3,2).

So the equation is: y - y1 = m(x - x1)

==> y - 2 = -3(x-3)

==> y-2 = -3x + 9

==> y = -3x + 9 + 2

==> y = -3x + 11

==> 3x + y = 11

==> the equation of the line that contains the points (3,2)and is parallel to the line the 3x+y=-3 is 3x + y = 11.

27)Given line is y = 5/2x - 4

==> slope of the line is 5/2

Perpendicular lines have the product of their slopes = -1

So slope of the perpendicular to the given line is -1/(5/2)

= -2/5

The line passes through (2,-5)

So the equation is: y - y1 = m(x - x1)

==> y-(-5) = (-2/5)(x-2)

==> y+5 = (-2/5)(x-2)

==> y = -2/5x + 4/5 - 5

==> y = -2/5x - 21/5

==> the equation of the line that contains the point (2,-5) and is perpendicular to the line y=5/2x-4 is y = -2/5x - 21/5

Good Luck!!!

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