Question 80808
Solve for x:
{{{5x^2+x+7 = 0}}} Apply the quadratic formula:{{{x = (-b+-sqrt(b^2-4ac))/2a}}}
{{{x = (-1+-sqrt(1^2-4(5)(7)))/2(5)}}} Simplify.
{{{x = (-1+-sqrt(1-140))/10}}}
{{{x = (-1+-sqrt(-139))/10}}}
The solutions are the "complex" numbers:
{{{x = ((-1 + sqrt(139)i))/10}}} and
{{{x = ((-1 - sqrt(139)i))/10}}}

If you need the approximate solutions:
{{{x = -0.1+(1.1790)i}}} and
{{{x = -0.1-(1.1790)i}}} to the nearest ten thousandth.