Question 10982
We have B in terms of G; what we want is to get G in terms of B.  This is done by isolating the G term through operations.


{{{B = 2(G-5)}}}
{{{B/2 = G-5}}} ... divide both sides by 2
{{{B/2 + 5 = G}}} ... add 5 to both sides


Thus, the value of G is {{{B/2 + 5}}}.


To verify this, we substitute the value of G we just obtained into the original equation for B:
{{{B = 2(G-5)}}}
{{{B = 2((B/2 + 5) - 5)}}}
{{{B = 2(B/2)}}}
{{{B = B}}} ... yup!