Question 10759
Let's see. 3 consecutive integers would be x, x + 1, and x + 2. If their total sum is 96, just add up all those integers:


{{{ (x) + (x+1) + (x+2) = 96 }}} <---- start here


{{{ x + x + 1 + x + 2 = 96 }}} <----- get rid of the parentheses


{{{ 3x + 3 = 96 }}} <---- combine the like terms


{{{ 3x = 93 }}} <----- subtract 3 from both sides


{{{ x = 31 }}} <------- One of those integers is 31. If one of the others is x + 1, then it would be 32. If the last one was x + 2, then it would be 33. So, the 3 consecutive integers that add up to 96 are 31, 32, and 33.