<PRE><B>Question 76349</B>
he square root of (x-11) - the square root of x= -1
:
{{{sqrt(x-11) - sqrt(x)}}} = -1
:
{{{sqrt(x-11) = sqrt(x) - 1}}}; added {{{sqrt(x)}}} to both sides
:
(x - 11) = x - {{{-2sqrt(x)}}} + 1; Squared both sides, FOILed {{{(sqrt(x) - 1)^2}}}
:
{{{2sqrt(x)}}} = x - x + 1 + 11, arranged terms to have the radical on the left by itself
:
{{{2sqrt(x)}}} = +12
:
4x = 144; squared both sides
:
x = 144/4
:
x = 36
:
:
Check our solution:
{{{sqrt(36-11) - sqrt(36)}}} = -1
   5 - 6 = -1
:
How about this? Could you follow this procedure OK?
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