Question 75651
3X^2+BX-3
(3X-3)(X+1) BX=0X
OR
(3X+1)(X-3) BX=-8X
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5X^2+BX+1
(5X-1)(X-1) BX=-6X
OR
(5X+1)(X+1) BX=6X
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-3X^2+BX-3
(-3X-3)(X+1) BX=-6X
OR
(3X+1)(-X-3) BX=-10X
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DON'T KNOW IF THERE IS A SIMPLE RULE BUT TRY THIS ONE
WHEN THE AX^2 TERM HAS AN (A) VALUE=1 THEN THE SUM OR DIFFERENCE OF THE FACTORS OF THE (AX^2+BX+C) (C) VALUE=THE (B) VALUE - THEN IT IS FACTORABLE. 
EXAMPLE:
X^2+9X+20 FACTORS OF 20 ARE 4&5 WHICH WHEN ADDED EQUAL 9 THUS:
(X+4)(X+5)=X^2+9X+20 FACTORS OF -20 ARE -4&5 OR 4&-5 AND WHEN ADDED MUST  EQUAL -1
X^2-X-20=(X+4)(X-5)
X^2-21X+20 FACTORS HERE ARE -1&-20, 1&20 BUT THE SET THAT ADDS UP TO -21 ARE 
-1&-20
(X-1)(X-20)