Question 10098
i assume you mean {{{3^(4x+5) = 9}}}?


If so, then rewrite it as {{{3^(4x+5) = 3^2}}}


now take the log of both sides, but a log to base-3, since log-base3 of 3^2 is 2 etc


4x+5 = 2
4x = -3
x = -3/4


check...
if x was -3/4, then the power becomes 4(-3/4) + 5 --> 2


so we end up with 3^2 = 9 which is correct.


Hope this is clear? ;-)


jon.