Question 9490
I think prince abubu has a boo-boo!  Recheck that solution for a careless error!


-(x-3)+2(x-1)<3(x+4)
-x + 3 + 2x - 2 < 3x + 12
x + 1 < 3x + 12


Personally, when solving inequalities, I prefer to keep the variables on the left side, and take numbers to the right side.  When students DON'T do this, they tend to make more errors than the way I suggested!


So, let's subtract 3x from each side to get the variables on the left side:
x - 3x + 1 < 3x - 3x + 12
-2x + 1 < 12


Subtract 1 from each side:
-2x + 1 - 1 < 12 - 1
-2x < 11


Divide both sides by -2.  This is a critical step, since you must CHANGE the direction of the inequality, because you divided (or multiplied) both sides by a NEGATIVE number!!
{{{ (-2x)/-2 < 11/-2 }}}
{{{x> -11/2}}}


R^2 at SCC