Question 70740
Find the trigonometric form of the product [sqrt6cis(2pi/3)|sqrt6cis(-5pi/6)].
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General Rule: (acisb)(dcisf) = (ad)cis(b+f)

= (sqrt6)^2 cis[(2/3)pi + (-5/6)pi]

= 6 cis[(-1/6)pi]
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Cheers,
Stan H.