Question 70004
solve the following triangles. given A=35 degrees, b=2, c=3
:
This would be side/angle/side which can be handled using the law of cosines
:
a^2 = b^2 + c^2 - 2bc*cos(A)
:
a^2 = 2^2 + 3^2 - 2(2*3)*cos(35)
:
a^2 = 4 + 9 - 12*.819
:
a^2 = 13 - 9.83
:
a = Sqrt(3.17)
:
a = 1.78
:
You can use the law of sines to find the other angles:
{{{sin(A)/a}}} = {{{sin(B)/b)}}}
:
{{{sin(35)/1.78}}} = {{{sin(B)/2)}}}
:
{{{.574/1.78}}} = {{{sin(B)/2)}}}
:
1.78*sin(B) = .574 * 2
:
sin(B) = {{{1.147/1.78}}}
:
sin(B) = .644468
:
B = 40.1 ~ 40 degrees
:
Angle C = 180 - 35 - 40 = 105 degrees