<PRE><B>Question 8640</B>
Do you mean {{{2/x + 1/(2x) = 7}}}


Assuming that this is the case, the LCD for the entire problem is 2x, so multiply both sides of the equation by 2x:
{{{ (2x)*( 2/x) + (2x)* (1/(2x)) = 2x*7}}}


This eliminates all the denominators:
4 + 1 = 14x
5= 14x


Divide both sides by 14:

x= {{{5/14}}}


R^2 at SCC</PRE>