Question 66724
Do you mean {{{sqrt(x-8) = sqrt(13+x) }}}??

If so, then square both sides of the equation:
{{{x-8=13+x}}}

{{{-8=13}}}


There is no solution to this equation.  Perhaps I misunderstood what you meant.  Did you perchance mean:  {{{sqrt(x) -8=sqrt(13+x) }}} or maybe {{{sqrt(x-8)=sqrt(13) + x}}}??  Maybe you can indicate with parentheses exactly what is supposed to be inside the square root symbols.


R^2 at SCC