Question 66550
3x^3y^5m^2)(x^2y)^-2
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x^2y^0y^-4 


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[3x^3y^5m^2)(x^-4y^-2)]/[x^2y^-4]

=[3x^-1 y m^-2]/[x^2y^-4]

=[3y^5] / [x^3 m^2]

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Cheers,
Stan H.