```Question 64255
hey. so im new to learning algebra they just put me in it.
can you show me how to slove these problems below?

Triangle ABC woth A(-4,-1)B(-2,-1)C(-4,4) is rotated 180* about the orgin. what are the coordinates of the vertices of the figure after the triangle is rotated?
LET O BE THE ORIGIN.IMAGINE LINE OA IS ROTATED BY 180.THEN IT WILL BE ALONG THE SAME LINE OA BUT LYING ON THE OPPOSITE SIDE.IF THE NEW POSITION OF A IS A'THEN A'OA WILL BE ONE LINE WITH OA=OA'.HENCE X AND Y COORDINATES OF THE POINT WILL REMAIN THE SAME IN MAGNITUDE BUT CHANGE IN SIGN.THAT IS IF A IS (H,K),THEN A' WILL BE (-H,-K).
HENCE THE NEW CCORDINATES OF A,B,C WILL BE (4,1);(2,1);(4,-4) RESPECTIVELY.

state the range of the relation.{(-2,5)(0,-1)(-1,4)(-1,5)}
RANGE IS SET OF  VALUES OF Y OR SECOND COORDINATES={5,-1,4,5}

solve: y= 2x-7 if the domain is {-3,1,5}
AT X=-3...........Y=2*(-3)-7=-13
AT X=1............Y=2*1-7=-5
AT X=5............Y=2*5-7=3

If g(x)= 3x squared- 4x+1, what is the value of g(-2)
G(-2)=3*(-2)^2-4(-2)+1=3*4+8+1=21

find the solution set of 2x-y squared=8 give the replacemebt set
AT X=2 AND Y=-2,WE HAVE
LHS=2*2-(-2)=6....IS NOT EQUAL TO RHS  OF 8
AT X=4 AND Y=0,WE GET
LHS=2(4)-0=8=RHS..........IS THE SOLUTION SET.
{(2,-2)(6,22)(6,2)(4,0)(12,-4)}
thanks.```