Question 752966
(k)/(k+4) +(4)/(k-4) = (4k+12)/(k+4)(k-4) 
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Multiply thru by (k+4)(k-4) to get:
k(k-4) + 4(k+4) = 4k+12
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k^2 +16 = 4k+12
k^2 - 4k + 4 = 0
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(k-2)^2 = 0
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k = 2 with multiplicity 2
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Cheers,
Stan H.
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