Question 752451

Reversing the digits of Gyver's age gives Ed's age with a difference of 18 years. If the sum of the digits of each age is 6, how old is Gyver?

Thanks a bunch for answering this :


Based on info, Gyver is YOUNGER than Ed


Let the tens and units digits of Gyver’s age be T and U, respectively
Then: 10T + U = 10U + T – 18 ------ 10T – T + U – 10U = - 18 ----- 9T – 9U = - 18 ---- 9(T – U) = 9(- 2)
T – U = - 2 ------ eq (i)
Also, T + U = 6 ----- eq (ii)
2T = 4 ------ Adding eqs (i) & (ii)
T, or tens digit of Gyver’s age = {{{4/2}}}, or 2


2 – U = - 2 ------ Substituting 2 for T in eq (i) 
- U = - 2 – 2 
- U = - 4
U, or units digit of Gyver’s age = {{{(- 4)/- 1}}}, or 4


Therefore, Gyver is {{{highlight_green(24)}}} years-old


You can do the check!!


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