Question 752002
(2yz)^2(xyz)-2


When the site's triple bracket tags are placed, the expression looks like {{{(2yz)^2(xyz)-2}}}


The exponent 2 applies to everything inside the grouping symbols.
{{{(2*2*y^2*z^2)(xyz)-2}}}


The other grouped expression is not exponentiated but is present as a factor, so this means show the resulting multiplication:
{{{2*2*y^2*z^2*xyz-2}}}
{{{2*2*x*y*y^2*z*z^2-2}}}  because factors in a product can be legally moved to different positions within that product
{{{2*2*y*y^2*z^2*z*x-2}}}
ANSWER: {{{highlight(4xy^3z^3-2)}}}  and that is as far as you can do with it.