Question 751425
graph this equation: x^2-4y=0 and state vertex & focus
x^2-4y=0
x^2=4y
Parabola opens upward
Basic form of equation:(x-h)^2=4p(y-k), (h,k)=(x,y) coordinates of the vertex
vertex:(0,0)
axis of symmetry: x=0 or y-axis
4p=4
p=1
focus: (0,1) (p-distance above vertex on the axis of symmetry)
see graph below:
y=x^2/4
{{{ graph( 300, 300, -10, 10, -10, 10,x^2/4) }}}