<PRE><B>Question 749711</B>
Solve By Substitution:
-3x + 4y = -18
x = -2y - 4

Substitute x = -2y - 4 into the first equation.

-3x + 4y = -18

-3(-2y - 4) + 4y = -18

-3 * -2y = 6y

-3 * -4 = 12

We now have:

6y + 12 + 4y = -18

Combine like terms:

6y + 4y = 10y

10y + 12 = -18

Subtract 12 from each side of the equation.

10y + 12 - 12 = -18 - 12

Combine like terms:

12 - 12 = 0

-18 - 12 = -30

Therefore:

10y = -30

Divide each side by 10

10y/10 = -30/10

y = -3



Now substitute y = -3 into the second equation.

x = -2y - 4

x = -2(-3) - 4

-2(-3) = 6

x = 6 - 4

6 - 4 = 2

x = 2





Answer:

x = 2 and

y = -3














Lennox Obuong
Algebra Tutor
Nairobi, Kenya
Email: obuong3@aol.com</PRE>