Question 749851
{{{32=2*2*2*2*2=2^5}}} and {{{0.6=3/5}}} so
{{{32^0.6=(2^5)^(3/5)=2^((5*(3/5)))=2^3=8}}}
 
{{{1/16)=(1/2)*(1/2)/(1/2)/(1/2)=(1/2)^4}}} and {{{0.75=3/4}}} so
{{{(1/16)^0.75=((1/2)^4)^(3/4)=(1/2)^((4*(3/4)))=(1/2)^3=1/8}}}
 
Putting it all together:
{{{32^0.6-(1/16)^0.75=(2^5)^(3/5)-((1/2)^4)^(3/4)=2^((5*(3/5)))-(1/2)^((4*(3/4)))=2^3-(1/2)^3=8-1/8=64/8-1/8=63/8}}}