Question 748766

{{{1+log(6,(r-5))=1}}}

{{{log(6,(r-5))=1-1}}}

{{{log(6,(r-5))=0}}}...........since {{{log(6,1)=0}}}, substitute it

{{{log(6,(r-5))=log(6,1)}}}...if so, then

{{{r-5=1}}}

{{{r=1+5}}}

{{{r=6}}}