Question 739055
log(3)(x-4)=2-log(3)(x+4)
{{{log(3,(x-4)+log(3,(x+4))=2)}}}
{{{log(3,(x-4))+log(3,(x+4))=log(3,(9))}}}
{{{log(3,(x-4)(x+4))=log(3,(9))}}}
(x-4)(x+4)=9
x^2-16=9
x^2=25
x=5
or 
x=-5(reject, (x-4)>0))