Question 736110

first write {{{2x+3y+6=0}}} in {{{slope-intercept}}} form {{{y=mx+b}}} where {{{m}}} is slope and {{{b}}} is {{{y-intercept}}}

{{{2x+3y+6=0}}}...solve for {{{y}}}

{{{3y=-2x-6}}}

{{{y=-(2/3)x-6/3}}}

{{{y=-(2/3)x-2}}}

so, the slope of the line with the equation {{{2x+3y+6=0}}} is {{{m=-(2/3)}}}