Question 734960
Interesting that you showed your given line in almost correctly point-slope form as plain text.  Your post is now edited for this correction to eliminate possible confusion, ------


The slope that you will want is the negative reciprocal of {{{(-(2/3))}}}, which will be {{{3/2}}}.  You now expect an equation for your desired line to be {{{y-v=(3/2)*(x-u)}}}, where the point (u, v) is any point which you want your line to contain. The given point for (u, v) is (-8, 3), so just substitute those values:

{{{y-(3)=(3/2)*(x-(-8))}}}
and the rest to be done is a couple steps of arithmetic.