Question 730436
{{{1 day = 24 hours = 1440min=86400sec}}}


so, in {{{1sec}}} you will have {{{1000/86400=0.011574074074074074074074074074074years}}}



But if you want to find out an exact number you must do some research, I might be wrong here, but a year with 1 extra day occurs once every 4th year, so:

1000/4 = 250 this is 250 years with 1 extra day, which changes the math into making us take into account that 250 years of those 1000 has 366 days instead of 365

{{{1000years +250 days=1000/86400+250/86400=0.011574074074074074074074074074074+0.0028935185185185185185185185185185=

0.014467592592592592592592592592519}}}


Or, you can forget leap years and use a more sane representation of years such Julian years ({{{365.25}}} days, exactly) or tropical years ({{{365.24218967}}} days at the epoch J2000.0) 

{{{365.25*24=8766h=31557600sec}}}

so in {{{1000}}} years will be {{{365.25*1000= 365250}}} days

{{{365250 /31557600=0.011574074074074074074074074074074}}}