Question 727110
The net worth of senior citizens is normally distributed with mean equal to $225,000 and standard deviation equal to $35,000. What is the probability that a single randomly selected senior citizen will have a net worth less than $300,000
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z(300,000) = (300,000-225000)/35000 = 75/35 = 2.1429
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P(x > 300,000) = P(z > 2.1429) = 0.0161
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Cheers,
Stan H.