Question 722984

If the numerator and denominator of a fraction are each increased by 1, the result is 35; but if the numerator and denominator are each decreased by 1, the result is 59.
Let the fraction be ab. Write down two equations satisfied by a and b:
(i)
(ii)
Find the fraction. ab


{{{(a + 1)/(b + 1) = 35}}} ---- 35b + 35 = a + 1 ----- a – 35b = 34 ---- eq (i)


{{{(a - 1)/(b - 1) = 59}}} ---- 59b – 59 = a – 1 ----- a – 59b = - 58 ---- eq (ii)


Solving, a = {{{highlight_green(168.1667)}}}, and b = {{{highlight_green(3.833333)}}}


You can do the check!!


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